(x^2-9)(2x+7)/(x-1)^2

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Solution for (x^2-9)(2x+7)/(x-1)^2 equation:


D( x )

(x-1)^2 = 0

(x-1)^2 = 0

(x-1)^2 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:+oo)

((x^2-9)*(2*x+7))/((x-1)^2) = 0

( 2*x+7 )

2*x+7 = 0 // - 7

2*x = -7 // : 2

x = -7/2

( x^2-9 )

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in { -7/2, 3, -3 }

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